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A cannonball is fired horizontally from the top of a cliff. the cannon is at height h = 80.0 m above ground level, and the ball is fired with initial horizontal speed v0. assume acceleration due to gravity to be g = 9.80 m/s2 .assume that the cannon is fired at time t=0 and that the cannonball hits the ground at time tg. what is the y position of the cannonball at the time tg/2?

Respuesta :

Answer;

= 60 m

Explanation;

s = 80 m

= ½at² = ½ * 9.8m/s² * t² → t = 4.04 s  

At any time 0 ≤ t ≤ 4.04 s, height is  

y = Yo + ½at² = 80 m - 4.9m/s² * t²  

so at t = 4.04s/2 = 2.02 s,  

y = 80 m - 4.9m/s² * (2.02s)² = 60 m  

(so it drops 15 m during the first 2.02 s and 60 m during the second 2.02 s)

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