Respuesta :
Answer:
- Conc. of K+ ions = 0.90 M
- Coc. of SO4∧-2 = 0.45 M
Explanation:
Data Given:
Conc. of H2SO4 = 0.450
As sulphoric acid is a strong electrolyte, it completely dissociate into ions.
H2SO4 ⇆ 2K+ + SO4∧-2
.450 M K2SO4 means that there is .450 mols of K2SO4 in every liter of solution.
K2SO4 : K+ K2SO4 : SO4∧-2
1 = 2 1 = 1
0.450 = 2× 0.450 = 0.90 0.450 = 0.450×1 = 0.450
Result:
Conc. of potassium ion will be 0.90M
Coc. of sulphate ions will be 0.45 M
0.450 M [tex]\rm \bold{K_2SO_4 }[/tex] solution dissociate to form 0.9 M Potassium ion and 0.45 M sulfate ion.
Explanation:
The given reaction,
As we Potassium sulfate is a strong electrolyte, hence it will completely dissociate.
[tex]\rm \bold{K_2SO_4 \rightarrow 2K^++ SO_4^2^- }[/tex]
1 moles of Potassium sulfate dissociate to form 2 moles of Potassium ion and 1 mole of sulfate ion
[tex]\rm \bold{K_2SO_4 }[/tex] concentration = 0.450 M
The concentration of
[tex]\rm \bold{ K^+ = 2\times 0.45}\\\\\rm \bold{ K^+ = 0.9}\\\\\rm \bold{ SO_4^2_- = 0.45}[/tex]
Hence, can conclude that 0.450 M [tex]\rm \bold{K_2SO_4 }[/tex] solution dissociate to form 0.9 M Potassium ion and 0.45 M sulfate ion.
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