Respuesta :
GIVEN
the dimensions ofrectangular prism are
length = 54 in
breadth = 32.25in
height = 24.5 in
formula
volume of the rectangular prism = length×breadth×height
= 54 ×32.25×24.5
= 42997.5 in³
first statement is false because the volume of the rectangular prism in two significant digit.
Second statement is false because the volume of the rectangular prism in two significant digit.
FORMULA
surface area of a rectangular prism = 2(wl+hl+hw)
by putting the value of the length , breadth & height
we get
= 2 (54×32.25 + 32.25×24.5 + 24.5×54)
= 7709.25 in²
= 7709.3 in²(approx)
Third statement is true the surface area of the container is rounded to ones place.
Hence proved
Answer:
Statement 1 is false.
Statement 2 is false.
Statement 3 is true.
Step-by-step explanation:
Given : The dimensions of a storage container in the shape of a rectangular prism are 54 in × 32.25 in × 24.5 in.
To find : Choose True or False for each statement.
Solution :
The dimensions of a rectangular prism are 54 in × 32.25 in × 24.5 in.
Statement 1 - The most precise dimension has 4 significant digits.
The most precise dimension is 54 and it has two significant digits.
So, Statement 1 is false.
Statement 2 - Written using the correct number of significant digits, the volume of the container has 3 significant digits.
The volume of the container,
[tex]V=l\times b\times h[/tex]
[tex]V=54\times32.25\times 24.5[/tex]
[tex]V=42666.75\ in^3[/tex]
The volume of the container is not having 3 significant digits.
So, Statement 2 is false.
Statement 3 - Written using the correct number of significant digits,the surface area of the container is rounded to the ones place.
The surface area of the container,
[tex]S=2(lb+ bh+ hl)[/tex]
[tex]S=2((54)(32.25)+(32.25)(24.5)+(24.5)(32.25))[/tex]
[tex]S=2(1741.5+790.125+790.125)[/tex]
[tex]S=2(3321.75)[/tex]
[tex]S=6643.5\ in^2[/tex]
So, Statement 3 is true the surface area of the container is rounded to ones place.
