Respuesta :

SOLUTION-

Here

[tex]m \angle BQR = 15.4^{\circ}[/tex]

As QB is the angle bisector so,

[tex]m \angle PQB = m \angle BQR[/tex]

∴ [tex]m \angle PQB= 15.4^{\circ}[/tex]

As,

[tex]m \angle PQR = m \angle PQB+m \angle BQR =15.4^{\circ}+15.4^{\circ} = 30.8^{\circ}[/tex]

∴  [tex]m \angle PQR= 30.8^{\circ}[/tex]

The measures of <PQB and m<PQR are 15.4 and 30.8degrees respectively given that m∠BQR is 15.4∘

The line that bisects an angle divides the angle into two equal parts.

If QB bisects ∠PQR, hence:

  • <PQB = <BQR
  • <PQR = 2<BQR

Given the following parameter:

m<BQR = 15.4degrees, hence <PQB = 15.4 degrees

Get m<PQR

<PQR = m<BQR + <PQB

<PQR = m<BQR + <BQR

<PQR = 2m<BQR

<PQR = 2(15.4)

<PQR = 30.8degrees

Hence the measures of <PQB and m<PQR are 15.4 and 30.8degrees respectively

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