Respuesta :
SOLUTION-
Here
[tex]m \angle BQR = 15.4^{\circ}[/tex]
As QB is the angle bisector so,
[tex]m \angle PQB = m \angle BQR[/tex]
∴ [tex]m \angle PQB= 15.4^{\circ}[/tex]
As,
[tex]m \angle PQR = m \angle PQB+m \angle BQR =15.4^{\circ}+15.4^{\circ} = 30.8^{\circ}[/tex]
∴ [tex]m \angle PQR= 30.8^{\circ}[/tex]
The measures of <PQB and m<PQR are 15.4 and 30.8degrees respectively given that m∠BQR is 15.4∘
The line that bisects an angle divides the angle into two equal parts.
If QB bisects ∠PQR, hence:
- <PQB = <BQR
- <PQR = 2<BQR
Given the following parameter:
m<BQR = 15.4degrees, hence <PQB = 15.4 degrees
Get m<PQR
<PQR = m<BQR + <PQB
<PQR = m<BQR + <BQR
<PQR = 2m<BQR
<PQR = 2(15.4)
<PQR = 30.8degrees
Hence the measures of <PQB and m<PQR are 15.4 and 30.8degrees respectively
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