Respuesta :
The net ionic equation is
2Ag^+(aq) + SO4^2-(aq) → Ag2SO4 (s)
explanation
write the chemical equation for the reaction
2AgNO3 (aq) + Na2SO4 (aq)→ Ag2SO4 (s) + 2 NaNO3 (aq)
write the ionic equation
2Ag^+(aq) + 2 NO3^- (aq) +2 Na^+(aq) + SO4^2-(aq) → Ag2SO4 (s) +2 Na^+(aq) + 2NO3^-
cancel the spectator ions (NO3^- and Na^+)
the net ionic equation is therefore
= 2Ag ^+(aq) + SO4^2-(aq) → Ag2SO4(s)
Ionic equations are defined as the net equation in which spectator ions are eliminated and only equation of participating ions are taken. The net ionic equation of silver nitrate and sodium sulphate is:
- [tex]\begin{aligned}\text{AgNO}_3(\text{aq})+\text{Na}_2\text{SO}_4(\text{aq})\rightarrow\text{Ag}_2\text{SO}_4(\text{s})+\text{NaNO}_3(\text{aq})\end{aligned}[/tex]
The chemical equation of silver nitrate and sodium sulphate will form silver sulfate. The balanced chemical equation of the reaction will be:
- [tex]\begin{aligned}2\text{AgNO}_3(\text{aq})+\text{Na}_2\text{SO}_4(\text{aq})\rightarrow\text{Ag}_2\text{SO}_4(\text{s})+2\text{NaNO}_3(\text{aq})\end{aligned}[/tex]
Now, writing the net ionic equation, we get:
- [tex]\begin{aligned}2\text{Ag}^++2\text{NO}_3^-+2\text{Na}^++\text{SO}^{2-}_4\rightarrow\text{Ag}_2\text{SO}_4+2\text{Na}^++2{\text{NO}^-_3\end{aligned}[/tex]
Cancelling out the similar compounds on reactant's and product's side, the net ionic equation can be represented as:
- [tex]\begin{aligned}2\text{Ag}^+(\text{aq})+\text{SO}^{2-}_4(\text{aq})\rightarrow\text{Ag}_2\text{SO}_4(\text{s})\end{aligned}[/tex]
Therefore, the ionic equation is the reaction between silver and sulphate to from silver sulphate.
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https://brainly.com/question/11628165?referrer=searchResults
