An airplane flies between two points on the ground that are 500 km apart. the destination is directly north of the origination of the flight. the plane flies with an air speed of 120 m/s. if a constant wind blows at 10.0 m/s due west during the flight, what direction must the plane fly relative to the air to arrive at the destination?

Question

contestada

Respuesta :

Blacklash Blacklash · Answer 1 · 2018-10-01T19:46:49+02:00

Answer:

Plane must fly 4.78⁰ due north to east at a speed of 120 m/s to reach destination.

Explanation:

Let the east point towards positive X-axis and north point towards positive Y-axis.

Speed of plane = 120 m/s

Wind speed = 10.0 m/s due west = -10 m/s

So plane must have an horizontal speed of 10 m/s to cancel this wind speed

Horizontal speed of plane = u cos θ = 120*cos θ = 10

Angle θ =85.22⁰ from positive horizontal axis.

Angle from North axis towards East required = 90 - 85.22 = 4.78⁰

So plane must fly 4.78⁰ due north to east at a speed of 120 m/s to reach destination.

snehashish65 snehashish65 · Answer 2 · 2022-02-15T18:59:30+01:00

The plane must fly 4.78⁰ due north to east at a speed of 120 m/s to reach its destination.

What is Speed?

The distance covered by any object per unit time is known as speed. Mathematically, speed equals the ratio of distance and time.

Given data -

The distance between the two points is, d = 500 km.

The speed of air is, v = 120 m/s.

The speed of wind due west is, v' = 10.0 m/s.

Let the east point towards the positive X-axis and the north point towards the positive Y-axis.

The horizontal speed of the plane is,

v' = v cos θ

here, θ is the angle from the positive horizontal axis.

Solving as,

10 = 120*cos θ

θ = 85.22⁰

The Angle from North axis towards East is,

θ' = 90 - 85.22

θ' = 4.78⁰

Thus, we can conclude that the plane must fly 4.78⁰ due north to east at a speed of 120 m/s to reach its destination.

Learn more about the speed here:

https://brainly.com/question/7359669