Suppose you have a group of 10 children consisting of 4 girls and 6 boys. how many four -person teams can be chosen that consist of two girls and two boys

Respuesta :

4 girls      and  6 boys

2(2 girls) and  3(2 boys)

   ₄C₂       x     ₆C₂

=     6        x       15

=            90

Answer: 90 different teams

There are 90 ways a four -person teams can be chosen that consist of two girls and two boys

How to determine the number of selection?

The distribution is given as:

Gender    Girls   Boys

Total         4        6

Selection  2        2

The number of selection is calculated using:

[tex]n = ^4C_2 * ^6C_2[/tex]

Evaluate the combination expressions

n = 6 * 15

Evaluate the product

n = 90

Hence, there are 90 ways a four -person teams can be chosen that consist of two girls and two boys

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