Respuesta :
We use the first equation of motion, to calculate the acceleration of the car
[tex]v = u + at[/tex]
Here, v is final velocity and its value is 100 km/h = 100(1000/3600) = 27 .78 m/s and u is initial velocity as car accelerates from rest so its value zero and t is time taken and its value is given 4.80 s.
Therefore,
[tex]27 .78 \ m/s = 0 + a \times 4.80 \ s \\\\ a = 5.79 \ m/s^2[/tex].
Now the magnitude of force,
[tex]F= ma = 68 \ kg \times 5.79 \ m/s^2 = 393 .52 \ N[/tex].
Thus, the magnitude of force by passenger experience during the acceleration is 393 .52 \ N.
The magnitude of force, a 68.0 kg passenger experience during the acceleration is 323.52 N.
The formula of acceleration
[tex]\rm \bold{ a = \frac{v-u}{t} }[/tex]
Where,
v- velocity = 100km/h = 27 .78 m/s
u- initial vecity = 0
t = time = 4.8 s
put the values
[tex]\rm \bold{ a = 5.79m/s^2}[/tex]
Formula for force
F= ma
[tex]\bold{F = 68 kg\times 5.79m/s^2}\\\\\bold{F = 323.52N }[/tex]
Hence, we can conclude that the magnitude of force, a 68.0 kg passenger experience during the acceleration is 323.52 N.
To know more about Acceleration, refer to the link:
https://brainly.com/question/12550364?referrer=searchResults
