Answer:
If we consider vertical velocity both have same vertical velocity of [tex]\sqrt{2gH}[/tex]
Resultant velocity when stone hits the ground is more for thrown horizontally.
Explanation:
We have equation of motion, [tex]v^2=u^2+2as[/tex], where u is the initial velocity, u is the final velocity, s is the displacement and a is the acceleration.
When rock is dropped:
Initial velocity = 0 m/s , displacement = H and acceleration = g.
[tex]v^2=0^2+2gH\\ \\ v=\sqrt{2gH}[/tex]
When rock is thrown horizontally:
Considering vertical motion of rock
Vertical initial velocity = 0 m/s ,Vertical displacement = H and vertical acceleration = g.
[tex]v^2=0^2+2gH\\ \\ v=\sqrt{2gH}[/tex]
If we consider vertical velocity both have same vertical velocity of [tex]\sqrt{2gH}[/tex]
But stone thrown horizontally will have horizontal velocity also, so it has more velocity if we compare resultant velocity.
