Respuesta :
The absolute pressure is given by the equation,
[tex]P_{abs}=P_{atm}-P_{vac}[/tex]
Here, [tex]P_{abs}[/tex] is absolute pressure,[tex]P_{atm}[/tex] is atmospheric pressure and [tex]P_{vac}[/tex] is vacuum pressure.
Therefore,
[tex]P_{abs}=98 kPa-80 kPa=18kPa[/tex]
The gage pressure is given by the equation,
[tex]P_{gage}=P_{abs}-P_{atm}[/tex].
Thus,
[tex]P_{gage}=18kPa-98 kPa=-80 kPa[/tex].
In kn/m^2,
The absolute pressure,
[tex]P_{abs}=18kPa(\frac{1kN/m^2}{kPa}) =18\ kN/m^2[/tex]
The gage pressure,
[tex]P_{gage}=-80kPa(\frac{1kN/m^2}{kPa}) =-80\ kN/m^2[/tex].
In lbf/in2
The absolute pressure,
[tex]P_{abs}=18\ kPa(\frac{1.45\times 10^{-1}\ lbf/in^2 }{1kPa} )=2.6\ lbf/in^2[/tex]
The gage pressure,
[tex]P_{gage}=-80kPa(\frac{1.45\times 10^{-1}\ lbf/in^2 }{1kPa} )=-11.6\ lbf/in^2[/tex]
In psi,
The absolute pressure,
[tex]P_{abs}=18\ kPa(\frac{1.45037738\times 10^{-1}\ psi }{1kPa})=2.610\ psi[/tex].
The gage pressure,
[tex]P_{gage}=-80kPa(\frac{1.45037738\times 10^{-1}\ psi }{1kPa} )=-11.6030\ psi[/tex]
In mm Hg
The absolute pressure,
[tex]P_{abs}=18kPa(\frac{7.5\ mm\ of\ Hg }{1\ kPa})= 135\ mm\ of\ Hg[/tex]
The gage pressure,
[tex]P_{gage}=-80kPa(\frac{7.5\ mm\ of\ Hg }{1\ kPa})=-600\ mm\ of\ Hg[/tex]
