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if an object is projected upward with an initial velocity of 127 ft per sec, its height h after t seconds is h=−16t2+127t. Find the height of the object after 4 seconds.

Respuesta :

frika

You are given a function [tex]h(t)=-16t^2+127t.[/tex] This function shows you the dependence of height from time.

To find the height of the object after 4 seconds, you should substitute t=4 into the function expression:

 [tex]h(4)=-16\cdot 4^2+127\cdot 4=-16\cdot 16+508=-256+508=252\ ft.[/tex]

Answer: the height of the object after 4 seconds will be 252 ft.

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