kensieco3294 kensieco3294
  • 22-09-2018
  • Mathematics
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Find the domain of f(x)= sqrt2-9x

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tramserran
tramserran tramserran
  • 22-09-2018

f(x) = [tex]\sqrt{2 - 9x}[/tex]

2 - 9x ≥ 0

  - 9x ≥ - 2

     [tex]\frac{-9x}{-9} \geq \frac{-2}{-9}[/tex]

     x ≤ [tex]\frac{2}{9}[/tex]

Interval Notation: (-∞, [tex]\frac{2}{9}[/tex]]

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