Given the mass percentage of HCl solution = 15.00 %
This means that 15.00 g HCl is present in 100 g solution
Moles of HCl = [tex]15.00 gHCl*\frac{1 mol HCl}{36.46 g HCl} =0.411molHCl[/tex]
Density of the solution = 1.075 g/mL
Calculating the volume of solution from density and mass:
[tex]100 g *\frac{1mL}{1.075 g} =93.0 mL[/tex]
Converting volume from mL to L:
[tex]93.0 mL * \frac{1 L}{1000 mL} =0.093 L[/tex]
Calculating the molarity of HCl solution from moles and volume:
[tex]\frac{0.411 mol}{0.093 L} =4.42 mol/L[/tex]
The molarity of the solution would be 4.42 M
The density of the solution is 1.075 and the solution contains 15.00% by mass of HCl.
The volume of the solution can be found by:
Density = mass/volume
1.075 = 100/volume
volume = 100/1.075
= 93.02 ml
Molarity of solutions = number of moles/volume in dm3
Moles = mass/molar mass
moles of HCl in the solution = 15/36.5
= 0.411 moles
Molarity of the solution = 0.411/93.02 x 10^-3
= 4.42 M
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