Respuesta :
Answer : The oxidizing element is N and reducing element is O.
[tex]KNO_{3}[/tex] is act as an oxidizing agent as well as reducing agent.
Explanation :
An Oxidizing agent is the agent which has ability to oxidize other or a higher in oxidation number.
Reducing agent is the agent which has ability to reduce other or lower in oxidation number.
The given reaction is :
[tex]KNO_{3} \rightarrow KNO_{2} +O_{2}[/tex]
[tex]KNO_{3}[/tex] act as an oxidizing agent.
The oxidation number of N in [tex]KNO_{3}[/tex] is calculated as:
(+1)+(x)+3(-2) = 0
x = +5
And the oxidation number of N in [tex]KNO_{2}[/tex] is calculated as:
(+1)+(x)+2(-2) = 0
x = +3
From the oxidation number method, we conclude that the oxidation number reduced this means [tex]KNO_{3}[/tex] itself get reduced to [tex]KNO_{2}[/tex] and it can act as an oxidizing agent.
[tex]KNO_{3}[/tex] act as a reducing agent.
[tex]KNO_{3} \rightarrow KNO_{2} +O_{2}[/tex]
The oxidation number of O in [tex]KNO_{3}[/tex] is calculated as:
(+1)+(+5)+3(x) = 0
x = -2
The oxidation number of O in [tex]O_{2}[/tex] is Zero (o).
Now, we conclude that the oxidation number increases this means [tex]KNO_{3}[/tex] itself get oxidized to [tex]O_{2}[/tex] and it can act as reducing agent.
Answer:
The oxidized element is, oxygen.
The reduced element is, nitrogen.
The oxidizing agent is, nitrogen.
The reducing agent is, oxygen.
Explanation:
