Answer:
Option C is the correct answer
Explanation:
We have equation of motion , [tex]s= ut+\frac{1}{2} at^2[/tex], s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
In this case initial velocity = horizontal velocity = 100 m/s, acceleration = 0 [tex]m/s^2[/tex], we need to calculate displacement when time = 1.3 seconds.
Substituting
[tex]s= 100*1.3+\frac{1}{2} *0*1.3^2 = 130 meter[/tex]
So, bullet will travel a distance of 130 meter in 1.3 seconds.
Option C is the correct answer
