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gmany

[tex]\left\{\begin{array}{ccc}2x-y=6\\2x-2y=4&|\text{add 2y to both sides}\end{array}\right\\\left\{\begin{array}{ccc}2x-y=6\\2x=4+2y&|\text{divide both sides by 2}\end{array}\right\\\left\{\begin{array}{ccc}2x-y=6\\x=2+y\end{array}\right\\\\\text{Substitute x=2+y to the first equation}\\\\2(2+y)-y=6\ \ \ \ |\text{use distributive property}\\(2)(2)+(2)(y)-y=6\\4+2y-y=6\\4+y=6\ \ \ \ \ |\text{subtract 4 from both sides}\\\boxed{y=2}\\\\\text{Put the value of y to the second equation}\\\\x=2+2\\\boxed{x=4}[/tex]

[tex]Answer:\ D.\ (4,\ 2)[/tex]

sid071

Hey there!!

The two equations we have :

2x - y = 6 ---------- ( 1 )

2x - 2y = 4 ----------- ( 2 )

Now subtract the second equation from the first equation :

2x - y = 6 ------ ( 1 )

- 2x + 2y = -4 ------ ( 2 )

y = 2

We have got the answer for y which is 2

Now we will have to substitute this value in place of y and find x

2x - y = 6

2x - 2 = 6

2x = 8

x = 4

For a ordered pair, the coordinates are written as ( x , y )

We got x = 4 and y = 2

Hence, the answer is ( 4 , 2 ) option d

Hope my answer helps!

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