The perimeter of a shape is the sum of the side lengths of the shape.
The perimeter of polygon GHJK is 10 units
Given that:
[tex]G = (2,4)[/tex]
[tex]H = (2,3)[/tex]
[tex]J =(-2,3)[/tex]
[tex]K =(-2,4)[/tex]
First, we calculate the side lengths using distance formula
[tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]
So, we have:
[tex]GH = \sqrt{(2 - 2)^2 + (4 - 3)^2} = \sqrt{0^2 + 1^2} = 1[/tex]
[tex]HJ = \sqrt{(2 -- 2)^2 + (3 - 3)^2} = \sqrt{4^2 + 0^2} = 4[/tex]
[tex]JK = \sqrt{(-2 -- 2)^2 + (3 - 4)^2} = \sqrt{0^2 + 1^2} = 1[/tex]
[tex]KG = \sqrt{(-2 - 2)^2 + (4 - 4)^2} = \sqrt{(-4)^2 + 0^2} = 4[/tex]
Then, we add the side lengths to get the required perimeter
[tex]P =GH + HJ + JK + KG[/tex]
[tex]P =1 + 4 + 1 + 4[/tex]
[tex]P =10[/tex]
Hence, the perimeter of the polygon is 10 units
See attachment for image of the polygon
Read more about perimeters at:
https://brainly.com/question/10153419
