-5,1 and 2,1
M= y2-y1/x2-x1
M=1-1/2-(-5)
M=0/7
M=0
Y=mx+b
(2,1)
1=0(2)+b
1=b
Y=1
First, let's find the slope of the line segment that passes through the given poins (-5,1) and (2,1). (Note: Please use parentheses here.
1-1
m = -------------- = 0. The slope of this segment is zero; the segment is horiz.
2-(-5)
The desired line is therefore horiz. It passes thru (-5,1) and (2,1). Note that the y-coordinates are both 1. Thus, the equation of this horiz. line is y = 1.
