Calculate the acceleration of the object during the first two seconds

Answer:
The acceleration of the object during the first two seconds is 1.5 [tex]\frac{m}{s^{2} }[/tex].
Explanation:
At t = 2 s, velocity of the object is 3 m/s
At t = 0 s, velocity of the object is 0 m/s
Acceleration is define as rate of change of velocity with time.
∴Acceleration = [tex]\frac{v_{f} -v_{i} }{t_{f} - t_{i} }[/tex]
Acceleration = [tex]\frac{v_{2} -v_{0} }{t_{2} - t_{0} }[/tex]
Acceleration = [tex]\frac{3-0 }{2-0 }[/tex]
Acceleration = 1.5 [tex]\frac{m}{s^{2} }[/tex]
The acceleration of the object during the first two seconds is 1.5 [tex]\frac{m}{s^{2} }[/tex].