Starting at home Omar traveled a pill to the gift store for 30 minutes such as 10 mph event travels back home along the same path down hill at a speed of 30 mph what is his average speed for the entire trip from home to the gift store and back

Respuesta :

We know Distance formula is  Distance = speed * time

[tex]time = \frac{distance}{speed}[/tex]

Let, the distance Omar traveled = d  and speed is 10 miles per hour

Time taken  t for the first trip  [tex]t = \frac{d}{10}[/tex]

Let, the distance Omar traveled = d  and speed is 30 miles per hour

Time taken  t for the return  trip  [tex]t = \frac{d}{30}[/tex]

Total time taken =  [tex]\frac{d}{10} + \frac{d}{30} = \frac{3d+d}{30} = \frac{4d}{30}[/tex]

Now, [tex]Average \ speed = \frac{total \  distance}{total \ time \ taken}[/tex]

Total distance = d+d= 2d

Average speed = [tex]\frac{2d}{\frac{4d}{30}}[/tex] = [tex]2d * \frac{30}{4d} = 15[/tex]

His average speed for the entire trip from home to the gift store and back is

15 miles per hour