Answer:
Bolt will travel a distance of 3750 meter horizontally from the point where it left the plane until it lands on the ground.
Explanation:
We have equation of motion , [tex]s= ut+\frac{1}{2} at^2[/tex], s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
Here bolt has horizontal and vertical motion, but the horizontal velocity remains same because there is no acceleration acting in the horizontal direction.
In this case initial velocity = 150 m/s, time taken to reach ground = 25 seconds and acceleration is zero.
Substituting
[tex]s= 150*25+\frac{1}{2}*0*25^2\\ \\ s=3750 meter[/tex]
So bolt will travel a distance of 3750 meter horizontally from the point where it left the plane until it lands on the ground.
