The empirical formula of the compound is calculated as follows:
Given that
It contains 85.63% carbon, and 100-85.63= 14.37 % hydrogen
now assume that the amount of compound is100 g thus there is 85.63 g C and 14.37 g H
NOW divide these percentages by the molar mass of the elements to get a number of moles for each substance.
NUMBER OF MOLES = AMOUNT IN G / MOLAR MASS
Carbon: 85.63/12 = 7.1
Hydrogen: 14.37/1 = 14.3
Now arrange these in a ratio as follows:
C:H
7.1/7.1 :14.3/7.1
1:2
divide through by the smallest number
Therefore, the empirical formula is CH2
Then calculate the molar mass of that molecule:
(1x12) + (2x1) = 14
Here the molar mass of compound is 56.10 g/mol
Since, 14 goes into 56.10 g/mol 4 times thus the molecular formula is : C4H8
The molecular formula of the compound is [tex]C_4H_8[/tex].
Empirical formula tell us the ratio of each molecule present in a compound.
Given,
Carbon -85.63%
100 – 85.63 = 14.37% hydrogen
Assuming the amount of compound is 100 g
So, carbon = 85.63
Hydrogen = 14.37 g
Calculating the mole of molecule:
Number of moles = mass / molar mass
[tex]Carbon = \dfrac{85.63}{12} = 7.1[/tex]
[tex]Hydrogen = \dfrac{14.37}{1} = 14.3[/tex]
Calculating the ratio by dividing the number of moles by the smaller value:
[tex]C:H = \dfrac{7.1}{7.1} :\dfrac{14.3}{7.1} = 1:2[/tex]
Therefore, the empirical formula is [tex]CH_2[/tex]
Calculating the molar mass of given molecule
[tex](1\times12) + (2\times1) = 14[/tex]
Here, the molar mass of the compound is given 56.10 g/mol.
Now, divide the given molar mass by calculated molar mass
[tex]\dfrac{56.10}{14} = 4[/tex]
The empirical formula will be four times.
Thus, the empirical formula is [tex]C_4H_8[/tex]
Learn more about empirical formula, here:
https://brainly.com/question/11588623
Since, 14 goes into 56.10 g/mol 4 times thus the molecular formula is : C4H8
