[tex]\dfrac{3}{4y+2}=x\\\\\dfrac{3}{4y+2}=\dfrac{x}{1}\ \ \ \ |\text{cross multiply}\\\\(4y+2)(x)=(3)(1)\ \ \ \ |\text{use distributive property}\\\\(4y)(x)+(2)(x)=3\\\\4xy+2x=3\ \ \ \ |\text{subtract 2x from both sides}\\\\4xy=3-2x\ \ \ \ |\text{divide both sides by 4x}\neq0\\\\\boxed{y=\dfrac{3-2x}{4x}}[/tex]