Respuesta :
solution: Mr. Schwartz will need to order more wheels after building 12 cars.
explanation:
Mr. Schwartz begins with total number of wheels = 85
he has to order more wheels once he left with less than 40 wheels
so min. no. of wheels he can use before ordering more wheels = 85-40 = 45
Mr. Schwartz uses 4 wheels to build 1 car
Mr. Schwartz uses 45 wheels to build 45÷4 = 11.25 cars
then, if he builds 12 cars then he needs 12×4 = 48 wheels
total supply of wheels he begins with = 85
wheels he used to build 12 cars = 48
so total number of wheels remaining  are = 85-48 = 37
since 37 is less than 40 so after building 12 cars Mr. Schwartz need to order more wheels.
The inequality that can be used to find the number of cars, x, Mr. Schwartz builds before he places an order for more wheels is 11
How to form mathematical expression from the given description?
You can represent the unknown amounts by the use of variables. Follow whatever the description is and convert it one by one mathematically. For example if it is asked to increase some item by 4 , then you can add 4 in that item to increase it by 4. If something is for example, doubled, then you can multiply that thing by 2 and so on methods can be used to convert description to mathematical expressions.
For this case, we are specified that:
- Current amount of wheel that Mr. Schwartz have = 85
- Each toy car needs the amount of wheel = 4
- Mr. Schwartz plans to order more wheels once he has < 40 wheels left.
- The number of cars is denoted by 'x'
Now, as the number of wheel is an integer, the amount of wheels which is less than 40 but closest to 40 and integer is 39.
Thus, when the number of wheels left becomes 39, Mr Schwartz will order more wheels.
As we have:
Total wheel = Wheels that he will use + 39 wheels that he won't use before ordering more wheels
85 = Wheels that he will use + 39
Wheels that he will use = 85 - 39 = 46
Since each car needs 4 wheels, let he build 'x' cars before ordering more wheels from those 46 wheels, then:
[tex]x \leq \dfrac{46}{4}[/tex]
(divided 46 wheels in lot of size 4, and 46 may or may not be fully divided, as not all integers are multiple of 4, and therefore, 46/4 is not going to be the number of cars that he will build, so we used [tex]\leq[/tex] ("less than or equal to" sign))
Solving further, we get:
[tex]x \leq \dfrac{46}{4} = 11.5\\\\x = 11[/tex]
(as x needs to be integers as number of cars cannot be in fraction, for this case at the least).
Thus, the inequality that can be used to find the number of cars, x, Mr. Schwartz builds before he places an order for more wheels is 11
Learn more about inequalities here:
https://brainly.com/question/11901702