Please answer to receive ten points. I'll vote who answers first the brainliest if its correct. 
 What is the perimeter of △ABC with vertices at A(−11, 4) , B(−7, 8) , and C (−4, 4) ?

Please round your final answer to the nearest tenth.

A. 6.8
B. 14
C. 17.7
D. 106

Respuesta :

frika

The distance between points [tex]P_1(x_1,y_1)[/tex] and [tex]P_2(x_2,y_2)[/tex] can be calculated using formula

[tex]P_1P_2=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.[/tex]

1.

[tex]AB=\sqrt{(-7-(-11))^2+(8-4)^2}=\sqrt{16+16}=\sqrt{32}=4\sqrt{2}\approx 5.657.[/tex]

2.

[tex]AC=\sqrt{(-4-(-11))^2+(4-4)^2}=\sqrt{49+0}=\sqrt{49}=7.[/tex]

3.

[tex]CB=\sqrt{(-7-(-4))^2+(8-4)^2}=\sqrt{9+16}=\sqrt{25}=5.[/tex]

Then

[tex]P_{ABC}=5.657+7+5=17.657\approx 17.7[/tex]

Answer: correct choice is C.