Respuesta :
Answer:- 3.12 g carbon tetrachloride are needed.
Solution:- The balanced equation is:
[tex]CH_4+CCl_4\rightarrow 2CH_2Cl_2[/tex]
From given actual yield and percent yield we will calculate the theoretical yield that would be further used to calculate the grams of carbon tetrachloride.
percent yield formula is:
percent yield = [tex](\frac{actual}{theoretical})100[/tex]
[tex]65.5=(\frac{2.25}{theoretical})100[/tex]
[tex]theoretical=(\frac{2.25(100)}{65.5})[/tex]
theoretical = 3.44 g
From balanced equation, there is 2:1 mol ratio between dichloethane and carbon tetrachloride.
Molar mass of dichloroethane is 84.93 gram per mol and molar mass of carbon tetrachloride is 153.82 gram per mol.
[tex]3.44gCH_2Cl_2(\frac{1molCH_2Cl_2}{84.93gCH_2Cl_2})(\frac{1molCCl_4}{2molCH_2Cl_2})(\frac{153.82gCCl_4}{1molCCl_4})[/tex]
= [tex]3.12gCCl_4[/tex]
So, 3.12 grams of carbon tetrachloride are needed to be reacted.
