What is the radius for the circle given by the equation? (Please help gmanyp)

Equation of a circle is: (x - h)² + (y - k)² = r² ; where (h,k) is the center and r is radius
So, (x - 2)² + y² = 14 has a center at (2,0) and radius of √14 = 3.7416
Answer: r = 3.742
The equation of a circle:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
where
(h, k) - the coordinates of a center
r - the radius
We have:
[tex](x-2)^2+y^2=14\\\\(x-2)^2+(y-0)^2=(\sqrt{14})^2[/tex]
[tex]Answer:\ r=\sqrt{14}\approx3.742[/tex]