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A ghost on a 135 feet cliff perpendicular (at 90 degrees) to the ground looks down at an angle of 16 degrees and sees a
werewolf. How far away is the ghost from the werewolf approximately? How far away is the wolf from the base of the cliff? Sketch the
triangle that matches this scenario with a ruler and protractor, and use this diagram and scales to solve for these distances between
the ghost, wolf and cliff. Explain how you got your answer.

Respuesta :

carlosego

To solve this problem you must apply the proccedure shown below:

1. You can make the diagram attached, where the ghost is identified as G and the the werewolf as W. The distance between both of them is y and the distance of the werewolf from the base of the cliff is x.

2. Let's calculate y:

[tex]Cos(16)=\frac{135}{y}[/tex]

[tex]y=\frac{135}{Cos(16)}[/tex]

[tex]y=140.44[/tex] ft

3. Now, let's calculate x:

[tex]Tan(16)=\frac{x}{135}[/tex]

[tex]x=(135)(Tan(16))[/tex]

[tex]x=38.71[/tex] ft

The answer are:

  • The ghost is 140.44 feet from the werewolf.
  • The werewolf is 38.71 feet from the base of the cliff.
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