Consider the given equation:
[tex]n-2 = \frac{10n+4}{2}[/tex]
Cross multiplying in the given equation, we get
[tex](n-2) \times 2 = 10n+4[/tex]
Applying distributive property which states [tex]a(b+c) = ab+ac[/tex], we get
[tex](n \times 2) - (2 \times 2) = 10n+4[/tex]
[tex]2n -4 = 10n+4[/tex]
Adding '4' on both the sides, we get
[tex]2n-4+4 = 10n+4+4[/tex]
[tex]2n = 10n+8[/tex]
Subtracting '10n' from both the sides of the equation, we get
[tex]2n-10n = 10n+8-10n[/tex]
[tex]-8n = 8[/tex]
Dividing by '-8' in both the sides of the equation, we get
[tex]n= -1[/tex]
Therefore, the value of 'n' is -1.
