Respuesta :
#1
Volume of lead = 100 cm^3
density of lead = 11.34 g/cm^3
mass of the lead piece = density * volume
[tex]m = 100 * 11.34 = 1134 g[/tex]
[tex]m = 1.134 kg[/tex]
so its weight in air will be given as
[tex]W = mg = 1.134* 9.8 = 11.11 N[/tex]
now the buoyant force on the lead is given by
[tex]F_B = W - F_{net}[/tex]
[tex]F_B = 11.11 - 11 = 0.11 N[/tex]
now as we know that
[tex]F_B = \rho V g[/tex]
[tex]0.11 = 1000* V * 9.8[/tex]
so by solving it we got
V = 11.22 cm^3
(ii) this volume of water will weigh same as the buoyant force so it is 0.11 N
(iii) Buoyant force = 0.11 N
(iv)since the density of lead block is more than density of water so it will sink inside the water
#2
buoyant force on the lead block is balancing the weight of it
[tex]F_B = W[/tex]
[tex]\rho V g = W[/tex]
[tex]13* 10^3 * V * 9.8 = 11.11[/tex]
[tex]V = 87.2 cm^3[/tex]
(ii) So this volume of mercury will weigh same as buoyant force and since block is floating here inside mercury so it is same as its weight = 11.11 N
(iii) Buoyant force = 11.11 N
(iv) since the density of lead is less than the density of mercury so it will float inside mercury
#3
Yes, if object density is less than the density of liquid then it will float otherwise it will sink inside the liquid