The numbers are "x" and "y", therefore, we suggest this system of equations:
x-y=14
xy=1800
We can solve by substitution method.
x=14+y
(14+y)y=1800
14y+y²=1800
y²+14y-1800=0
Now, we solve this square equation:
y=[-14⁺₋√(196+7200)] / 2=(-14⁺₋86)/2
We have two solutions:
y₁=(-14-86)/2=-50 ⇒x=14+y=14-50=-36
y₂=(-14+86)/2=36 ⇒x=14+y=14+36=50
Answer: we have two solutions:
Solution1: The first number is -36 and the other number is -50
Soltuion2: The first number is 50 and the other number is 36
