There are 10 employees all together.
-- The probability of selecting a woman first is 7/10 .
Then there are 6 women left, and 9 total.
-- The probability of selecting a woman second is 6/9 .
Then there are 5 women left, and 8 total.
-- The probability of selecting a woman third is 5/8 .
So the probability of all three selections is
(7/10) x (6/9) x (5/8)
= (7 x 6 x 5) / (10 x 9 x 8)
= 210 / 720
= 7 / 24 = about 29.2% .
