First, set up a system of equations:
a=b-160
a=2/3c
b=c+92
Then, pick a variable to solve for. I'll start with c.
So, we know that a=b-160 and b=c+92. That means the first equation could be written as a=(c+92)-160. Which simplifies to a=c-68, and a=2/3c, so really 2/3c=c-68. Simplify to 68=1/3c. to get rid of the fraction, multiply both sides by 3.
c=204.
Plug that into the other two equations,
a=2/3(204)
a=136
and
b=(204)+92
b=296
