Which equation correctly uses point (–2, –6) to write the equation of this line in point-slope form?

To convert the point (-2,-6) into point-slope equation of line form, you’ll need to just plug in the values in the standard form which is y-y1=m(x-x1). So in this case, what you will have is y+6=m(x+2). Since there is no value given for the slope, just plug in the value if ever you obtain it.

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carlosego carlosego · Answer 2 · 2018-07-24T17:24:23+02:00

For this case we have that by definition the equation of the line in point-slope form is given by:

[tex] y-yo = m (x-xo)
[/tex]

Where,

m: slope of the line

(xo, yo): point where the line passes

We have then:

[tex] (xo, yo) = (-2, -6)
[/tex]

Substituting values:

[tex] y - (- 6) = m (x - (- 2))
[/tex]

Rewriting the equation we have:

[tex] y + 6 = m (x + 2)
[/tex]

Answer:

An equation that correctly uses point (-2, -6) to write the equation of this line in point-slope form is:

[tex] y + 6 = m (x + 2) [/tex]