In triangle ABC, m∠BAC = 50°. If m∠ACB = 30°, then the triangle is triangle. If m∠ABC = 40°, then the triangle is triangle. If triangle ABC is isosceles, and AB = 6 and BC = 4, then AC =

In triangle ABC, m∠BAC = 50°. If m∠ACB = 30°, then the triangle is triangle. If m∠ABC = 40°, then the triangle is triangle. If triangle ABC is isosceles, and AB = 6 and BC = 4, then AC = 4

An isosceles triangle is a triangle in which two of its sides are equal.

The diagram below shows the diagrammatic representation of the values given in the question. The best way to solve for line AC is to use the cosine rule which can be computed by using the formula:

[tex]\mathbf{b^2= a^2 +c^2 -2ac Cos B}[/tex]
[tex]\mathbf{b^2= (4)^2 +(6)^2 -2(4)(6) Cos (40)}[/tex]
[tex]\mathbf{b^2= 16 +36 -48 *0.7660}[/tex]
[tex]\mathbf{b^2= 16 +36 -36.768}[/tex]
[tex]\mathbf{b^2= 15.232}[/tex]
[tex]\mathbf{b =\sqrt{15.232}}[/tex]
[tex]\mathbf{b \simeq 4.00}[/tex]

Therefore, we can conclude that the value of |AC| is 4.00

Learn more about the cosine rule here:

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