What is BC?
Any help?

Answer:
A. 10
Step-by-step explanation:
[tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]
[tex] d = \sqrt{(11 - 5)^2 + (-6 - 2)^2} [/tex]
[tex] d = \sqrt{6^2 + (-8)^2} [/tex]
[tex] d = \sqrt{36 + 64} [/tex]
[tex] d = \sqrt{100} [/tex]
[tex] d =10 [/tex]
Answer:
The answer is A) 10
Step-by-step explanation:
[tex]\sqrt{(-6-2)^{2}+(11-5)^{2}}[/tex]
[tex]\sqrt{64+36} \\\\= \sqrt{100} \\\\= 10[/tex]