They give us the cable tension t = 1500 newton. We assume that the mass of the cable is negligible compared to that of the tower.
We have a force t of 1500 Newton. This force has a vertical component on the y axis and a horizontal component on the x axis.
Of these two components of force, we are especially interested in calculating is the magnitude of the vertical component.
If the angle that it forms with the ground is 50 °, then the vertical component of the force is:
Fy = 1500sin (50)
Fy = 1149 N. <1200 N
The wire will not be loose
