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A ball is thrown into the air with an initial velocity of 22 meters per second. The quadratic function h(x)= -4.9t square +22t+5.5 represents the height of the ball above the ground, in meters, with respect to time t, in seconds. Determine h(3) and explain what it represents

Respuesta :

Answer:

Height of the ball after 3 seconds = 27.4 feet.

Step-by-step explanation:

h(t) = -4.9t^2 + 22t + 5.5

h(3) means the height of the ball at time 3 seconds after the ball was thrown.

h(3) = -4.9(3)^2 + 22(3) + 5.5

= Β 27.4 feet

onyebuchinnaji

The height reached by the ball when the time of motion is 3 seconds is 27.4 m.

The given parameters;

  • initial velocity of the ball, u = 22 m/s
  • height reached by the ball, [tex]h(t) = -4.9t^2 + 22t + 5.5[/tex]

The height reached by the ball when the time of motion, t, is represented as h(3).

The value of this height is calculated as;

h(3) = -4.9(3)Β² + 22(3) + 5.5

h(3) = -44.1 + 66 + 5.5

h(3) = 27.4 m

Thus, the height reached by the ball when the time of motion is 3 seconds is 27.4 m.

Learn more here: https://brainly.com/question/17042478

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