twilbon0 twilbon0

22-10-2018
Mathematics

contestada

Find the number of real number solutions for the equation. x^2-3x+8=0

Respuesta :

sqdancefan sqdancefan

22-10-2018

Answer:

None.

Step-by-step explanation:

The coefficients are a=1, b=-3, c=8, so the discriminant is ...

... b²-4ac = (-3)²-4(1)(8) = 9-32 = -23

This negative value means both the roots are complex.

Answer Link

konrad509 konrad509

22-10-2018

[tex]x^2-3x+8=0 \\\\\Delta=(-3)^2-4\cdot1\cdot8=9-32=-23[/tex]

[tex]\Delta<0[/tex] therefore, there are no real solutions.

Answer Link

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