Answer:
The images of PQR are P'=(8 , -6) , Q' = (8,6) and R' = (14 , -6)
Step-by-step explanation:
From the given graph:
the coordinates of PQR i.e,
P= (4, -3) , Q= (4,3) , R= (7,-3)
Given: the scale factor of 2 and center of dilation at origin i.e (0,0)
The mapping rule for the dilation applied to the triangle as shown below:
[tex](x, y) \rightarrow ( kx, ky)[/tex] where k represents the scale factor i.e, k=2 or we can write it as ;
[tex](x, y) \rightarrow (2x, 2y)[/tex]
For P = (4, -3)
The image P' = [tex](2\cdot 4 , 2\cdot (-3))[/tex]
⇒ P'= [tex](8, -6)[/tex]
Similarly for Q = (4, 3) and R = (7 , -3)
the image of Q' = [tex](2\cdot 4 , 2\cdot (3)) = (8 , 6)[/tex]
The image of R' = [tex](2\cdot 7 , 2\cdot (-3)) = (14 , -6)[/tex]
Now, plot the graph of PQR as shown in the attachment:
