Answer:
D) [tex]\frac{4x-3} {x+6}[/tex]
Step-by-step explanation:
First we have to factorize and then cancel the like terms.
Given,
[tex]\frac{4x^2-7x+3} {x^{2}+5x-6}\\=\frac{4x^2-3x-4x+3} {x^{2}+6x-x-6}\\=\frac{x(4x-3)-1(4x-3)} {x(x+6)-1(x+6)}\\=\frac{(4x-3)(x-1)} {(x+6)(x-1)}[/tex]
Now, we got the like term (x-1).
Canceling this like term we get
[tex]\frac{(4x-3)(x-1)} {(x+6)(x-1)}=\frac{4x-3} {x+6}[/tex]
Answer:
Your answer is D.
[tex]\frac{4x-3}{x+6}[/tex]
Step-by-step explanation:
First, you have to factor by grouping.
Next, factor using AC method.
Last, cancel the common factor.
Now all you do is rewrite the expression.
