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An individual that is homozygous dominant for type B blood and little finger shape mates with an individual that is heterozygous for type A blood and homozygous recessive for little finger shape . what are the predicted genotypic and phenotypic ratios for the cross?

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Answer:

Let "L" be the dominant allele for little finger shape and "l" be the recessive allele for the same.

It is given that a person is homozygous dominant for blood group B and little finger shape. Hence, the genotype would be [tex]I^BI^B[/tex]LL

The other person is heterozygous for blood group A and homozygous recessive for little finger shape. Hence, the genotype would be [tex]I^Aill[/tex]

The type of gametes formed by the first parent would be [tex]I^BL[/tex] only.

The type of gametes formed by second parent would be [tex]I^Al[/tex] and il.

The cross is shown in the attached figure.

According to the cross, we get two phenotype:

  • offspring with blood group AB and dominant little finger shape, and
  • offspring with blood group group B and dominant little finger shape.
  • They are present in 4 : 4 = 1 : 1

According to the cross, we get two genotype:

  • [tex]I^AI^BLl[/tex]
  • [tex]I^BiLl[/tex]
  • They are also present in 4 : 4 = 1 : 1.
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