A cashier has 26 bills consisting of the three times as many ones as fives, one less ten than fives, and the rest twenties. If the value is $120, find how many of each she has. Show work

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RenatoMattice RenatoMattice · Answer 1 · 2018-11-01T06:08:58+01:00

Answer: There are 5 fives .

There are 15 ones

There are 4 tens.

There are 2 twenties.

Step-by-step explanation:

Since we have given that

Number of bills a cashier has = 26

Let the number of fives be x

Let the number of ones be 3x

Let the number of tens be x-1

Let the number of twenties be given by

[tex]26-(x+3x+x-1)=26+1-5x=27-5x[/tex]

Amount from fives is given by

[tex]5\times x=5x[/tex]

Amount from ones is given by

[tex]3x\times 1=3x[/tex]

Amount from tens is given by

[tex]10\times (x-1)=10x-10[/tex]

Amount from twenties is given by

[tex]20\times (27-5x)=540-100x[/tex]

Now, according to question,

[tex]5x+3x+10x-10+540-100x=120\\\\-82x=120-540+10\\\\-82x=-410\\\\x=\frac{410}{82}\\\\x=5[/tex]

So,

There are 5 fives .

There are 15 ones

There are 4 tens.

There are 2 twenties.