Hello!
The area of the right triangle is 30 [tex]in^{2}[/tex]. The perimeter is 40 in.
First, we must find the measure of the hypotenuse of the triangle by using the Pythagorean Theorem.
[tex]a^{2}[/tex] + [tex]b^{2} = c^{2}[/tex]
[tex]8^{2} + 15^{2} = c^{2}[/tex]
64 + 225 = [tex]c^{2}[/tex]
√289 = [tex]c^{2}[/tex]
17 = [tex]c[/tex]
Now that we have all the side lengths, we can use the formulas to find the area and perimeter.
A = [tex]\frac{bh}{2}[/tex]
A = (15 × 8) ÷ 2
A = 30
P = a + b + c
P = 8 + 15 + 17
P = 40