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Answer

The area of the right triangle is 30 [tex]in^{2}[/tex]. The perimeter is 40 in.


Explanation

First, we must find the measure of the hypotenuse of the triangle by using the Pythagorean Theorem.

[tex]a^{2}[/tex] + [tex]b^{2} = c^{2}[/tex]

[tex]8^{2} + 15^{2} = c^{2}[/tex]

64 + 225 = [tex]c^{2}[/tex]

√289 = [tex]c^{2}[/tex]

17 = [tex]c[/tex]

Now that we have all the side lengths, we can use the formulas to find the area and perimeter.

AREA:

A = [tex]\frac{bh}{2}[/tex]

A = (15 × 8) ÷ 2

A = 30

PERIMETER:

P = a + b + c

P = 8 + 15 + 17

P = 40