9.03 mg
For this question I was supposed to make a search using the keyword "Chemical composition of the human body" and found the amount of Iodine as,
Element Atoms / 70 Kg Man
Iodine 5 × 10¹⁹
We can calculate amount of Iodine / 60 Kg as,
70 Kg Man contained = 5 × 10¹⁹ I atoms
So,
60 Kg Man will contain = X I atoms
Solving for X,
X = (60 Kg × 5 × 10¹⁹ I atoms) ÷ 70 Kg
X = 4.28 × 10¹⁹ I Atoms
Now, convert number of I atoms to Mass as,
Step 1: Calculate Moles of I,
Moles = Number of Atoms ÷ 6.022 × 10²³ Atoms.mol⁻¹
Putting value,
Moles = 4.28 × 10¹⁹ ÷ 6.022 × 10²³ Atoms.mol⁻¹
Moles = 0.00007116762 mol
Step 2: Calculate Mass of Mass:
Moles = Mass ÷ M.Mass
Solving for Mass,
Mass = Moles × M.Mass
Putting values,
Mass = 0.00007116762 mol × 126.90 g.mol⁻¹
Mass = 0.00903117141 g
Or,
Mass = 9.03 mg
