The are 4 different possibilities to draw a ten, namely a ten of the four different suits. The probability of the event is the ratio of the 4 possibilities and the total number of possible choices, whcih is 52:
P(E) = 4/52 = 1/13 or about 7.7%
The probability of getting an event is 0.08 and the probability of not getting an event P(E') is 0.92.
Given that, let E be the event that the card drawn is a 10.
We need to find the value of P(E').
A standard deck of cards has four suits: hearts, clubs, spades, and diamonds. Each suite has thirteen cards: ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen and king. Thus the entire deck has 52 cards total.
Probability of an event = P(E) [tex]=\frac{Number\ of \ favorable \ outcomes}{Total \ number \ of \ outcomes}[/tex].
Here, are the number of favorable outcomes=4 and the total number of outcomes=52.
So, P(E) [tex]=\frac{4}{52} =0.769=0.08[/tex].
As we know P(E)+P(E')=1
Now, 0.08+P(E')=1
⇒P(E')=1-0.08=0.92
Therefore, the probability of getting an event is 0.08 and the probability of not getting an event P(E') is 0.92.
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