Answer:
- The interval [9, 10] is 1,375% greater than the interval [5, 8].
- The interval [9, 10] is 14.75 times greater than the interval [5, 8].
Step-by-step explanation:
1. To solve this problem you must apply the following formula:
[tex]AverageRateOfChange=\frac{y_{2}-y_{1}}{x_{2}-y_{1}}[/tex]
2. Let's calculate the average rate of change of each interval:
a) Interval [9,10]:
[tex]=\frac{11,014-4,052}{10-9}=6,962[/tex]
b) Interval [5,8]:
[tex]=\frac{1,491-75}{8-5}=472[/tex]
3. The difference is:
[tex]6,962-472=6,490[/tex]
4. In percentage:
[tex](\frac{6,962-472}{472})(100)=1,375%[/tex]
5. You have that the interval [9,10] is 14.75 times greater than the interval [5,8], as you can see below:
[tex]\frac{6,962}{472}=14.75[/tex]
