Answer:
0.375 is answer
Step-by-step explanation:
Given that the math teacher gave her students two tests. On the first test, 80% of the class passed the test. But only 30% of the class passed both tests.
Let A - the students pass I test
B = students pass second test
Then P(A) = 80%=0.8 and P(AB) = 30% =0.30
Required probability =probability that a student passes the second test, given that they passed the first one
= P(B/A) = P(AB)/P(A)
= 0.30/0.80
=3/8
=0.375
Right answer is 0.375
