Answer:The probability of drawing a second orange ball, given that the first ball is orange is 1/7
Step-by-step explanation:
let A be the event of choosing one orange ball and B be the event of choosing second orange ball.
Given probability of choosing one orange ball is 1/5 i.e. P(A)=1/5
probability of choosing two orange balls without replacement is 1/35
i.e. P(A and B)=1/35
As both events are not independent then probability of drawing a second orange ball, given that the first ball is orange= P(B|A)=P(A and B)/P(A)=[tex]\frac{\frac{1}{35} }{\frac{1}{5} } =\frac{5}{35} =\frac{1}{7}[/tex]
therefore,the probability of drawing a second orange ball, given that the first ball is orange is 1/7.
