Answer:
1721 m/s
Explanation:
We can solve the problem by using the following SUVAT equation:
[tex]S=\frac{1}{2}at^2[/tex]
where S is the distance traveled, a is the acceleration of the plane and t is the time.
In this problem, a=3.20 m/s^2 and t=32.8 s, so we can find the distance traveled by the plane by substituting these numbers into the equation:
[tex]S=\frac{1}{2}(3.20 m/s^2)(32.8 s)^2=1721 m[/tex]
